Ex 33, 1 Solve the following pair of linear equations by the substitution method (vi) 3𝑥/2−5𝑦/3=−2 𝑥/3𝑦/2=13/6 Removing fractions from both equations 𝟑𝒙/𝟐−𝟓𝒚/𝟑=−2 Multiplying both equations by 6 6 × 3𝑥/2−"6 ×" 5𝑦/3="6 ×"−2 9x – 10y = − 12EduRev Class 10 Question is disucussed on EduRev Study Group bySolve the following pair of linear equations by the substitution method (3x)/2 (5y)/3 = 2, x/yy/2 = 13/6
4 4 Solving Simultaneous Equations Equations And Inequalities Siyavula
From the second equation, we have that x=\frac{53y}{2} Plugging this into the first equation, \left(\frac{53y}{2}\right)^2y^2(53y)6y35=0\\ \frac{9y^230y25Xy=3 xy=5 Step 1 Plot the above equation using the slope intercept form given as y=mxb where m is the slope and b is the yintercept when x=0 or at point (0,b) Step 2 Put xy=3 in slope intercept form or y=x3 where we added y3 to both sides of the equation Here the slope m=1 and b=3 Step 3Solve by Graphing xy=5 , xy=3, Subtract from both sides of the equation Subtract from both sides of the equation Multiply each term in by Tap for more steps Multiply each term in by Multiply Tap for more steps Multiply by Multiply by Simplify each term Tap for more steps Multiply by Multiply
Ex 4 6 13 Solve Linear Equations Using Matrix Method Ex 4 6
